Question

Calculate the empirical formula of a compound containing 42.1% sodium,
18.9% phosphorus and 39%oxygen. Work to 2 dp.
please ghelp me with this question...

Answer 1

Answer:

Element Percentage composition Atomic weight Relative No. of atoms Simplest ratio

Sodium 42.1 23 42.1/23 = 1.83 1.83/0.61 = 3

Phosphorus 18.9 31 18.9/31 = 0.61 0.61/0.61 = 1

Oxygen 39.0 16 39.0/16 = 2.44 2.44/0.61 = 4

Thus empirical formula is Na

3

Answer 2

Answer:

Boht hard question hai......