Question

calculate the empirical formula of compound that contain 26.6 % potasium 35.4 % chromium and 38.1 % oxygen​

Answer 1

Explanation:

Consider 100gm of the compound ,

Moles of k = 26.6/3.8 = 0.7

Moles of Cr = 36.4/52 = 0.68

Moles of O = 38.1/16 = 2.38

∴ Empirial Formula = K0.7 Cr0.68 O2.38

= K2 Cr2 O7

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