Question

calculate the energy of a photon corresponding to (1) wavelength 140mm and (2) wave number 10cm^-1=6.626×10^-34 Js​

Answer 1

Answer:

$\huge\colorbox{yellow}{Ouestion\:-}$

What is the energy of photons that corresponds to the wave number of

$2.5 \times {10}^{ - 5} {cm}^{ - 1}$

$\huge\colorbox{yellow}{Answer\:-}$

we know that wave number is reciprocal of the wave length.

$wave \: number = \frac{1}{ \gamma } = 2.5 \times {10}^{ - 5} {cm}^{ - 1}$

$speed \: of \: light \: (c) = 3 \times {10}^{8} {ms}^{ - 1} = 3 \times {10}^{10}cm. {s}^{? - 1} \: and \: h = 6.626 \times {10}^{ - 27} erg.s$

$\huge\underbrace\mathrm\red{According \: to \: Planck's \: \: theory}$

$E = \frac{hc}{ \gamma }$

$= 6.626 \times {10}^{ - 27} \times 3 \times {10}^{10} \times 2.5 \times {10}^{ - 5}$

$= 5.0 \times {10}^{ - 21}erg$

Hence, The energy of photons is 5.0×10^-21 erg

$\huge\colorbox{yellow}{Thank\:You}$

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