Question

Calculate the energy of neutron produced when a slow negative pion is
captured by a proton. Treat the neutron non-relativistically

Answer 1

Explanation:

HOPE ITS HELP U.............XD

Answer 2

Hence the energy of neutron is Σn = 6.6 mev

Explanation:

• 139 + 938 --> 939 + hv + e
• mn vn = Σ r / c
• Σn / Σ r = 1/2 mn vn^2 / c mn.vn = 1 / 2 Vc / c
• Σn / Σ r = 1/2  Σ r / mnc^2 = Σ / 1878
• Σn / Σ r + Σn = Σ r / 1878 + Σ r
• Σn / 138 = 138 - Σn / 1878 - 138 - Σn
• Σn = 138 - Σn / 2016 - Σn
• Σ n = 9 m eV
• mn . Vn = mn vn / √  (1 - β^2) = Σn  / c
• Σn = 6.6 mev

Hence the energy of neutron is Σn = 6.6 mev