Physics, asked by shripadghongade, 9 months ago

Calculate the energy of neutron produced when a slow negative pion is
captured by a proton. Treat the neutron non-relativistically

Answers

Answered by Anonymous
1

Explanation:

HOPE ITS HELP U.............XD

Attachments:
Answered by wajahatkincsem
1

Hence the energy of neutron is Σn = 6.6 mev

Explanation:

  • 139 + 938 --> 939 + hv + e
  • mn vn = Σ r / c
  • Σn / Σ r = 1/2 mn vn^2 / c mn.vn = 1 / 2 Vc / c
  • Σn / Σ r = 1/2  Σ r / mnc^2 = Σ / 1878
  • Σn / Σ r + Σn = Σ r / 1878 + Σ r
  • Σn / 138 = 138 - Σn / 1878 - 138 - Σn
  • Σn = 138 - Σn / 2016 - Σn
  • Σ n = 9 m eV
  • mn . Vn = mn vn / √  (1 - β^2) = Σn  / c
  • Σn = 6.6 mev

Hence the energy of neutron is Σn = 6.6 mev

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