Question

Calculate the energy of one mole of photons of radiation whose frequency is 5*1014

Answer 1

Answer:

3.3462 *10^-30

Explanation:

Energy = hv

= 6.62*10^-36*5*1014

=3.3462*10^-30

Answer 2

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Fequency is 5 × 10¹⁴ Hz

Answer:

$199.51 \: kJ \: mol {}^{ - 1}$

Explanation:

Energy (E) Of ome photon is guven by the expression

E = hV

$h = 6.626 \times {10}^{ - 34} Js$

$V = 5 \times {10}^{14} {s}^{ - 1}$

$E = (6.626 \times {10}^{ - 34} Js) \times (5 \times {10}^{14} {s}^{ - 1} )$

$= 3.313 \times {10}^{ - 19} J$

Energy of one mole of photons :-

$= (3.313 \times {10}^{ - 19} J) \times (6.022 \times {10}^{23} {mol}^{ - 1})$

$= 199.51 \: kJ \: {mol}^{ - 1}$