Question

Calculate the energy of radiation having a wavelength of 4000 A0 (angstrom) h=6.6*10-34​

Answer 1

Answer:

The energy of a photon of radiation having wavelength 3000 A is nearly:

Given wavelength = 3000A^∘ E = h ν c = hν v = clambda E = h. clambda = 6.626 x 1 0^-34 × 3 × 10^83000 × 10^-9 = 6.626 x 10^8 10^-9 = 6.626 x 1 ...