Physics, asked by thayanithi400210, 4 months ago

Calculate the energy of the moon orbiting the earth.​

Answers

Answered by TheUntrustworthy
95

The energy of the moon orbiting the earth is calculated below:

We know that energy of nth orbit, En = -K/n2 where K is a constant.

The change in energy is: ΔE=Eorbit−Esurface=2.98×1011J.

To get the kinetic energy, we subtract the change in potential energy from

Example 13.6, ΔU=3.32×1010J.

That gives us

Korbit=2.98×1011−3.32×1010

=2.65×1011J.

{\fcolorbox{blue}{black}{\orange{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: DecentMortal\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}

Answered by ritika123489
81

Explanation:

The energy of the moon orbiting the earth is calculated below:

We know that energy of nth orbit, En = -K/n2 where K is a constant.

The change in energy is: ΔE=Eorbit−Esurface=2.98×1011J.

To get the kinetic energy, we subtract the change in potential energy from

Example 13.6, ΔU=3.32×1010J.

That gives us

Korbit=2.98×1011−3.32×1010

=2.65×1011J.

Similar questions