calculate the energy transferred when 2A current flows through a 10 ohm
resistor for 30 mins.
Answers
Answered by
23
Voltage = current × resistance [from V = IR relation ]
V = 2 × 10 = 20 volts
We know, P = VI
P = 20 × 2 = 40W
We know, Power = Work/Time
⇒ Energy = Power × Time = 40 × 30 ×60 = 72000J = 72 KJ
V = 2 × 10 = 20 volts
We know, P = VI
P = 20 × 2 = 40W
We know, Power = Work/Time
⇒ Energy = Power × Time = 40 × 30 ×60 = 72000J = 72 KJ
Answered by
10
Acc. to Ohm's law
V = IR
V = 2 × 10 = 20 volts
We know, P = VI
P = 20 × 2 = 40 Watts
We know, Power = Energy/Time
So, Energy = Power × Time = P x t = 40 × 30 × 60 = 72000Joules = 72 Kilo Joules
V = IR
V = 2 × 10 = 20 volts
We know, P = VI
P = 20 × 2 = 40 Watts
We know, Power = Energy/Time
So, Energy = Power × Time = P x t = 40 × 30 × 60 = 72000Joules = 72 Kilo Joules
Similar questions
V = 2 × 10 = 20 volts
As, P = VI
P = 20 × 2 = 40W
We know, Power = Work/Time
⇒ Energy = Power × Time = 40 × 30 ×60 = 72000J = 72 KJ