calculate the energy transferred when 2A current flows through a 10 ohm resisitor for 30 min
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The energy transferred is 72000J or 72KJ...
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Answer:
72000 J
Explanation:
R=10ohm
I=2A
t=1800sec
H=I²RT
=(2)²(10)(1800)
=4×10×1800
= 40×1800
H= 7200 J..
therefore.
the heat transferred in 7200J or 72KJ
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