Physics, asked by rijuadhikary719, 1 year ago

calculate the energy transferred when 2A current flows through a 10 ohm resisitor for 30 min

Answers

Answered by TTG003

2

The energy transferred is 72000J or 72KJ...

Attachments:

Answered by archana747

0

Answer:

72000 J

Explanation:

R=10ohm

I=2A

t=1800sec

H=I²RT

=(2)²(10)(1800)

=4×10×1800

= 40×1800

H= 7200 J..

therefore.

the heat transferred in 7200J or 72KJ

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