Question

calculate the energy transferred when 2A current flows through a 10 ohm resistor for 30 minutes​

Answer 1

Please refer attachment

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Answer 2

$\huge \bold{ANSWER}$

Given the given energy is being converted to electrical energy.

Let a current of I be flowing through the conductor of Resistance R for the time t, when a source of potential difference is applied across its ends.

Due to flow of current I for the time t, the amount of charge passed is Q =I × t.

By defination of potential difference, work needed to move a charge Q through potential difference V is,

$\huge \boxed{W =Qt}$

But, Q = I × t.

$\huge \boxed{W =VIt}$

Thus, electrical energy W supplied by the source (battery or mains) is providing the current I for time t in the conductor under a potential difference V.

So, to find electrical energy,

Given the given energy is being converted to electrical energy.

◼CURRENT = 2A

◼RESISTANCE = 10 ohm

◼TIME = 30 minutes ,

convert minutes into seconds,

so, time will be, 30×60=1800sec

=10(V) × 2(I) × 1800(t)

= 10 × 2 × 1800

=36000J
or

$\bold{3.6 × {10}^{4}}$joules