Chemistry, asked by Aswad5137, 11 months ago

Calculate the enthalpy change when2.38 gm of co vaporizes at its normal boiling point

Answers

Answered by shivanshusingh97

0

:

ΔHvap of CO=+6.04kJmol−1

Molar mass of CO=28gmol−1

Energy required for vaporizing 28 g of CO =6.04kJ

Energy required for vaporizing 2.38 g of CO =6.04×2.3828=0.5134kJ

=513.4J

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