calculate the enthalpy of formation of liquid benzene (c6h6) given the enthalpies of carbon, hydrogen and benzene are -393.5kj, -285.83kj and -3267.0kj respectively.
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Standard enthalpy of hydrogenation of cyclohexen (- 119kJ mol-1) means the enthalpy of hydrogenation of one C = C double bond. Now benzene has three C = C double bonds, the enthalpy of the reaction would be = 3 * - 119 = - 357 kJ mol-1
Standard enthalpy of hydrogenation of cyclohexen (- 119kJ mol-1) means the enthalpy of hydrogenation of one C = C double bond. Now benzene has three C = C double bonds, the enthalpy of the reaction would be = 3 * - 119 = - 357 kJ mol-1
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