Question

Calculate the equilibrium constant of the reaction at 298 K .
Mg(s) + 2Ag+(aq) --> Mg2+(aq) +2Ag(s); E0 cell=+3.16 V

Answer 1

Dear Student,  

ΔG° = −nFE°cell

and, Δ G° = −RTlnKeq

Therefore,

nFE°cell = RTlnKeq

or, lnKeq = nFE °cell  RT

Here, n = 2 (as 2 electrons are involved)

F = 96500

E°cell = 3. 16 V

R = 8. 314 JK−1 mol−1

T = 298 K

or, lnKeq = = 246. 16

2×96500×3.16

8.314×298

or, Keq = e = 8. 05  So we get the answer as 8.05