Question

using integration find the area of triangle ABC whose vertices are A(2,3),B(4,7)and C(6,2)

Answer 1

thanksssss mark as BRAINLIST........

Answer 2

area of triangle ABC = 9 sq units whose vertices are A(2,3),B(4,7)and C(6,2)

Step-by-step explanation:

area of triangle ABC whose vertices are

A(2,3), B(4,7) and C(6,2)

area of triangle ABC = (1/2) | 2(7 - 2)  + 4(2 - 3)  + 6(3 - 7) |

= (1/2) | 2(5) + 4(-1) + 6(-4) |

= (1/2) | 10 - 4 - 24 |

= (1/2) | - 18 |

= 18/2

= 9

area of triangle ABC = 9 sq units

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