Calculate the equivalent capacitance between points A and B in the circuit
below. If a battery of 10 V is connected across A and B, calculate the charge
drawn from the battery by the circuit.
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This is the condition of wheat stone bridge, thus the capacitor of 50 ohm will not get supply of current.
Now the new circuit will have two series combination connected in parallel.
Net capacitance of upper series combination of C1 and C2
1/C(12) = 1/C(1) + 1/C(2)
1/C(12) = 1/10 + 1/20
C(12) = 20/3 microF
Net capacitance of lower series combination of C3 and C4
1/C(34) = 1/C(3) + 1/C(4)
1/C(34) = 1/5 + 1/10
C(34) = 10/3 microF
Now equivalent capacitance of circuit,
C(net) = 10/3 + 20/3
C(net) = 10 microF
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