Question

Calculate the equivalent conductivity of 1M of H2SO4 solution. Whose conductivity is 26×10 ohm-1 cm-1

Answer 1

Answer:

Normality=n

f

×Molarity

=2×1=2N

Now,

λeq=1000×

N

k

⇒λ

eq

=

2

1000×26×10

−2

=1.3×10

2

Scm

2

eq.

−1