Question

Calculate the equivalent resistance.

Answer 1

hey mate

Explanation:

from C toF

all resistance is in series

so r' = 2+3+5 = 10ohm

BG and CF are in parrallel

so 1/r" = 1/r2+1/r' = 1/10+1/10 = 1/5

r" = 5 ohm

from A TO H all are in series

Req = r1+r"+rlast = 2+5+5 = 12 ohm

hope it help u

Answer 2

Answer:

12ohm

Explanation:

As the 2,3&5ohm resistance r In series so, their equivalent resistance is

2+3+5=10ohm

Now this 10ohm &10 ohm resistance are in parallel.

So, their equivalent resistance is

10×10/10+10=5ohm

Now this 5, 2&5ohm resistance.are in series

So, their equivalent becomes

5+2+5=12ohm

Hope it helps

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