Question

calculate the equivalent resistance between points A and B in the given network of resistor.​

Answer 1

Answer:

The equivalent resistance between A & B is 16 ohms.

Explanation:

first you will take out the equivalent resistance of resistors C & D.

1/r1 + 1/r2 = 1/R

1/R = 1/10+1/10

1/R = 2/10 = 1/5

Thus, R = 5 ohms

Now calculate the equivalent resistance of the resistors B & total of (C & D = 5 ohms).

R = r1 + r2

R = 10 + 5 = 15 ohms

next calculate the equivalent resistance of resistors E & total of (B,C,D = 15 ohms)

1/R = 1/r1 + 1/r2

1/R = 1/10 + 1/15

1/R = 3+2/30 (Taking LCM)

1/R = 5/30 = 1/6

R = 6 ohm

now finally find the equivalent resistance of A & total of (B,C,D,E = 6 ohms)

R = r1 + r2

R = 10 + 6

R = 16 ohms. (ANSWER)

Note:

equation for resistors connected in series - R = r1 +r2

equation for resistors connected in parallel - 1/R = 1/r1 + 1/r2

Hope it helps. If you have further queries, add a comment.