Question

Calculate the equivalent resistance of the network across the points A and B shown in figure:

Answer 1

SOLUTION

Equivalent Resistance (given)

R1 = 4+8 = 12 ohm (they are in series)

R2= 4+8= 12 ohm (they are in series)

Now,

R1 & R2 are in parallel

$= > \frac{1}{</u></strong><strong><u>R</u></strong><strong><u>p} = \frac{1}{</u></strong><strong><u>R</u></strong><strong><u>1} + \frac{1}{</u></strong><strong><u>R</u></strong><strong><u>2} \\ \\ = > \frac{1}{</u></strong><strong><u>R</u></strong><strong><u>p} = \frac{1}{12} + \frac{1}{12} \\ \\ = > \frac{1}{</u></strong><strong><u>R</u></strong><strong><u>p} = \frac{2}{12} = > 6 \\ \\ = > </u></strong><strong><u>R</u></strong><strong><u>p = 6 \: ohm$

Hope it helps ☺️

Answer 2

 

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