Question

Pls answer me urgent ​

Answer 1

Answer:

HERE IS YOUR ANSWER ....

when time is (n-1) second, distance is

S n- 1 and when time is n second, distance is S n , then

S nth =

$u \: + \: \frac{a}{ 2} \: (2n - 1)$

#HOPE YOU UNDERSTAND IT

#HOPE IT'S HELPFUL TO U

#BRAINLY

Answer 2

S = u + $\dfrac{a(2n \: - \: 1)}{2}$

Here...

S is the distance, a is the acceleration, and nth is the time in seconds.

• $S_{n}$ = u + $\dfrac{a(2n \: - \: 1)}{2}$

• $S_{n+1}$ = u + $\dfrac{a[2(n \: + \: 1) \:+\:1}{2}$

=> $S_{n+1}$ = u + $\dfrac{a(2n \: + \: 2 \:+\:1}{2}$

=> $S_{n+1}$ = u + $\dfrac{a(2n \: + \: 1)}{2}$

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Now ...

$S_{n}$ + $S_{n+1}$ = u + $\dfrac{a(2n \: - \: 1)}{2}$ + u + $\dfrac{a(2n \: + \: 1)}{2}$

=> 50 = u + $\dfrac{2an \: - \: a}{2}$ + u + $\dfrac{2an \: + \: a}{2}$

=> 50 = $\dfrac{2u\:+\:2an \: - \: a\:2u\:+\:2an\:+\:a}{2}$

=> 50 × 2 = 4u + 4an

=> 100 = 4(u + an)

=> u + an = 100/4

=> u + an = 25

[As v = u + at]

=> v = 25

Then..

$\dfrac{v}{u}$ = $\dfrac{25}{5}$

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$\dfrac{v}{u}$ = 5 m/s

__________ [ ANSWER ]

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