Question

Calculate the equivalent resistance of the network across the points A and B.

Answer 1

Answer:

R1 => 4+8 = 12 ohm (they r in series)

R2=> 4+8 = 12 ohm (they r in series)

Now R1 & R2 are in parralel

=>> 1/Rp= 1/R1 + 1/R2 = 1/12 + 1/12 = 1/6

Rp = 6 ohm (total resistance)