calculate the equivalent resistance when a wire of resistance 10 ohm is divided into two equal parts and connected in parallel combination?
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Answered by
10
HEY DEAR_____❤️❤️❤️❤️❤️
HERE IS YOUR ANSWER:-
=>THE EQUIVALENT RESISTANCE WILL BE 1/10 IN BOTH PARTS.
=>PROOF,
=>1/R1 + 1/R2 = 10 (PARALLEL COMBINATION).
=>PUT THE VALUE OF R1 AND R2 = 10
=>1/10 + 1/10 = 10
=> 1 + 1 /10 + 10 = 10
=> 2/20 = 10
=>SO,
=>20/2 = 10
=>10 = 10
HOPE IT WILL HELP YOU
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^_^
HERE IS YOUR ANSWER:-
=>THE EQUIVALENT RESISTANCE WILL BE 1/10 IN BOTH PARTS.
=>PROOF,
=>1/R1 + 1/R2 = 10 (PARALLEL COMBINATION).
=>PUT THE VALUE OF R1 AND R2 = 10
=>1/10 + 1/10 = 10
=> 1 + 1 /10 + 10 = 10
=> 2/20 = 10
=>SO,
=>20/2 = 10
=>10 = 10
HOPE IT WILL HELP YOU
<<<<❤️❤️❤️❤️>>>>
✌️✌️✌️✌️✌️✌️✌️
^_^
Answered by
10
=>THE EQUIVALENT RESISTANCE WILL BE 1/10 IN BOTH PARTS.
=>PROOF,
=>1/R1 + 1/R2 = 10 (PARALLEL COMBINATION).
=>PUT THE VALUE OF R1 AND R2 = 10
=>1/10 + 1/10 = 10
=> 1 + 1 /10 + 10 = 10
=> 2/20 = 10
=>SO,
=>20/2 = 10
=>10 = 10
HOPE IT HELPS U ✌️✌️✌️
=>PROOF,
=>1/R1 + 1/R2 = 10 (PARALLEL COMBINATION).
=>PUT THE VALUE OF R1 AND R2 = 10
=>1/10 + 1/10 = 10
=> 1 + 1 /10 + 10 = 10
=> 2/20 = 10
=>SO,
=>20/2 = 10
=>10 = 10
HOPE IT HELPS U ✌️✌️✌️
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