Question

Calculate the equivalent weight of sodium bicarbonate. ( Na=23,H=1,C=12,O=16)

Answer 1

Answer:

NaHCO3 = 23+1+12+3(16)

=36+48

=84 g

Answer 2

Answer:

The equivalent weight of sodium bicarbonate is 84.01 g/mol. Equivalent weight is the mass of a substance that is equivalent to one mole of the substance. In other words, it is the mass of a substance that contains the same number of molecules as one mole of any other substance.

Step 1: Determine the equivalent weight of sodium bicarbonate.

The equivalent weight of sodium bicarbonate is 84.01 g/mol.

Step 2: Divide the molecular weight by the number of moles in 1 mole of a substance.

The number of moles in 1 mole of a substance is 6.022x10²³.

Step 3: Divide the molecular weight by 6.022x10²³ to get the equivalent weight.

84.01 g/mol / (6.022 x 10²³) = 0.000139 g/mol

Step 4: Multiply the equivalent weight by the number of moles in 1 mole of a substance.

(0.000139 g/mol) x (6.022 x 10²³) = 84.01 g/mol

Thus, the equivalent weight of sodium bicarbonate is 84.01 g/mol.

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