Calculate the escape velocity of a body from the Earth's surface
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A satellite is revolving around theearth in a circular orbit of radius 7000 km. Calculate its period given that the escape velocityfrom the earth's surface is 11.2 km/s and g = 9.8 ms/s
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Hii dear,
● Answer- 11.2 km/s
● Explaination -
# Given-
g = 9.8 m/s
R = 6.4×10^6 m
# Formula-
Escape velocity of a satellite from earth's surface is calculated by-
ve = √(2gR)
ve = √(2×9.8×6.4×10^6)
ve = √125.44 × 10^3
ve = 11.2 × 10^3 m/s
ve = 11.2 km/s
Escape velocity of satellite from earth's surface is 11.2 km/s.
Hope that is useful...
● Answer- 11.2 km/s
● Explaination -
# Given-
g = 9.8 m/s
R = 6.4×10^6 m
# Formula-
Escape velocity of a satellite from earth's surface is calculated by-
ve = √(2gR)
ve = √(2×9.8×6.4×10^6)
ve = √125.44 × 10^3
ve = 11.2 × 10^3 m/s
ve = 11.2 km/s
Escape velocity of satellite from earth's surface is 11.2 km/s.
Hope that is useful...
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