Question

Calculate the escape velocity on the surface of the moon given the mass and radius of the moon to be 7.34x10²² kg and 1.74x10^6 m respectively.​

Answer 1

Answer:

2.3 km/s

Explanation:

V=✓2GM/R

=✓2×6.67×10^-11×7.3×10^22/1.74×10^6

=✓562.7×10^4

=23.7×10^2 m/s

=2.37km/s