Question

calculate the excess pressure inside a soap
bubble of radius 3x10^-3m, Surface tension of soap
as 20x103 N/m​

Answer 1

${ \huge\rm \pink {♡H}\rm \blue {A} \rm \purple {N}\ \rm \green{J} \rm\red {U}\ \rm \orange {H} \rm{U} \rm \gray{I♡}}$

Answer 2

Answer:

Given, radius of the soap bubble = r = 3×10^-3 m.

Given, surface tension of the soap bubble = 20×10^-3 N/m.

Excess Pressure of Soap Bubble = P = (4× Surface Tension)/r

= (4 × 20×10^-3) / 3×10^-3 = 26.67 N/m^2