Question

calculate the extent of hydrolysis of 0.005 M K2CrO4. [K2= 3.1 *10^-7 for H2CrO4]

Answer 1

HERE IS YOUR ANSWER

CrO4^-2 + HOH ==> HCrO4^- + OH^-

Kh = kb = (Kw/k2) =  

(HCrO4^-)(OH^-)/(CrO4^-2)

You know (CrO4^-2), Kw, and k2. (HCrO4^-) = (OH^-) = x.

Solve for x to determine (HCrO4^-), then extent hydrolysis = (HCrO4^-)/(CrO4^-2).

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Answer 2

CrO4^-2 + HOH ==> HCrO4^- + OH^-

Kh = kb = (Kw/k2) =

(HCrO4^-)(OH^-)/(CrO4^-2)

You know (CrO4^-2), Kw, and k2. (HCrO4^-) = (OH^-) = x.

By solving answer comes to be 0.25% (i.e. extent of hydrolysis)