Calculate the final concentration of NaCl after 1.5 litres of 0.100M NaCl solution is diluted to 3.5 litres with water with 3.5 litres of water
(A) 0.214 M, 0.714 M (B) 0.5 M, 0.7 M
(C) 0.414 M, 0.614 M (D) 0.0314 M, 0.414 M
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In this problem, we can use the formula:
m1v1 = m2v2
Where:
m1 = Initial concentration (molarity)
v1 = Initial volume
m2 = Final concentration (molarity)
v2 = Final volume
m1v1 = m2v2
0.1 x 1.5 = m2 x 3.5
0.15 = 3.5m2
m2 = 0.15/3.5
m2 = 0.043M
NOTE
In case 3.5 litres of water is added, the final volume would be 1.5+3.5 =5 litres
and the calculation would be:
0.1 x 1.5 = m2 x 5
0.15 = 5m2
m2 = 0.15/5
m2 = 0.03M
m1v1 = m2v2
Where:
m1 = Initial concentration (molarity)
v1 = Initial volume
m2 = Final concentration (molarity)
v2 = Final volume
m1v1 = m2v2
0.1 x 1.5 = m2 x 3.5
0.15 = 3.5m2
m2 = 0.15/3.5
m2 = 0.043M
NOTE
In case 3.5 litres of water is added, the final volume would be 1.5+3.5 =5 litres
and the calculation would be:
0.1 x 1.5 = m2 x 5
0.15 = 5m2
m2 = 0.15/5
m2 = 0.03M
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