Question

Calculate the final temperature of 39 ml of ethanol initially at 18 ∘c upon absorption of 913 j of heat. (density of ethanol =0.789 g/ml)

Answer 1

q = mc delta t q is energy m is mass c is heat capacity delta t is temperature change 32 mL * .789 g/mL = 25.248 g the heat capacity of ethanol is 2.44 J/gC ( from source) 562 J = 25.248 g (2.44 J/gC) delta t 9.12 C = delta t delta t = t final - t initial 9.12 C = t final - 11 C 20.12 C = t final