Physics, asked by skullsoul, 7 months ago

Calculate the final velocity of a body which starts from rest acted by a constant acceleration of 2 m/s2 for a time interval of 5 minutes

Answers

Answered by santhi080700gmailcom
21

Explanation:

v=u+at

u=0

a=2m/s square

t=5minutes=300seconds

v=0+2×300

v=600m/s

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Answered by Rohit18Bhadauria
30

Given:

Initial velocity of body, u= 0 m/s

(Since, it starts from rest)

Acceleration of body, a= 2 m/s²

Time taken by body, t= 5 min= 300 s

To Find:

Final velocity of body

Solution:

We know that,

  • According to first equation of motion for constant acceleration

\pink{\boxed{\bf{v=u+at}}}

where,

v is final velocity of body

u is initial velocity of body

a is acceleration of body

t is time taken of body

\rule{190}{1}

Let the final velocity of given body be 'v'

So, on applying first equation of motion on given body, we get

\longrightarrow\rm{v=u+at}

\longrightarrow\rm{v=0+2(300)}

\longrightarrow\rm\green{v=600\:m/s}

Hence, final velocity of given body for the given time interval is 600 m/s.


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