Question

calculate the final volume of a gas x if the original pressure of the gas at STP is doubled and its temperature is increased 3 times

Answer 1

Let v1 be x v2 is unknown.
P1 is 1 atm P2 is 2 atm.
T1T2=3T1
P1V1/T1=P2V2/T2
1*x/T1=2xV2/3T1.
V2=3T1*x/T1*x
V2=3/2....

Answer 2

$\bold{\huge{SOLUTION \: :}}$

$\boxed{INITIAL\:\:CONDITIONS\:\: :}$

◼ P1 = 760 mm Hg

◼ V1 = V1 (say)

◼ T1 = 273 K

$\boxed{FINAL\:\:CONDITIONS\:\: :}$

◼ P2 = (2×760) mm Hg

◼ V2 = V2 (say)

◼ T2 = (3×273) K

______________________________

NOW, USING THE GAS EQUATION :

______________________________

P1V1/T1 = P2V2/T2

=> (760×V1)/273 = (1520×V2)/819

=> V2 = 1.5 V1

SO, the final volume is 1.5 times the initial volume of the gas at S. T. P. [ANSWER]