Physics, asked by nimi18, 1 year ago

calculate the force between the two charges when the charges are doubled and distance of separation is halved

Answers

Answered by Maryamkhan123
2
Force between two charges according to Columbs law is
F1 == kq1q2/r²

(k = 1/4πe•)

F when two charges are doubles and distance halved

F 2= k x 4 x (q1q2) ÷ (r/2)²

(The 2² in the double denominator comes to the numerator)
(And 2² = 4)

F2 == 4 x k x 4 x (q1q2)

F2 == 16 x k x q1q2

Hence F2 = 16 times F1

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