calculate the force between two Alpha particles kept at a distance of 0.02 mm in air
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Charge of alpha particle = 2e
Here e = charge of electron
F = kq₁q₂/r²
= 4ke²/r²
= 4 × (9 × 10⁹) × (1.6 × 10⁻¹⁹)² / (0.02 × 10⁻³)²
= 2.3 × 10⁻¹⁸ N
Coulombic Force between them is 2.3 × 10⁻¹⁸ N
Here e = charge of electron
F = kq₁q₂/r²
= 4ke²/r²
= 4 × (9 × 10⁹) × (1.6 × 10⁻¹⁹)² / (0.02 × 10⁻³)²
= 2.3 × 10⁻¹⁸ N
Coulombic Force between them is 2.3 × 10⁻¹⁸ N
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