Physics, asked by subhashmahadik196, 8 months ago

calculate the force between two charges of 1c separated by 10m in air.plz answer fast

Answers

Answered by nikhilmishra5577
1

Answer:

Force =

r

2

kq

1

q

2

=

(20×10

−2

)

2

9×10

9

×20×10

−3

×20×10

−3

=

4×10

−2

36×10

5

=9×10

7

N

Answered by harisreeps
0

Answer:

Two charges 1C and 1C are kept separated by a distance of 10m in the air the magnitude of the force between them​ is 9*10^{7}N

Explanation:

  • The interaction between two charges at rest is called electrostatic force
  • The coulomb's law gives the magnitude of the force in the air as

                     F=\frac{q_{1} q_{2} }{4\pi \varepsilon _0  r^{2} }

       where q_{1} ,q_{2}- the charges

       \frac{1}{4\pi \varepsilon _0}=9*10^{9}

       r- separation between the charges

From the question, we have

the charges are q_{1} =1C ,q_{2} =-1C

the distance between the charges r=10m

substitute the values, we get

/F/=\frac{9*10^{9}*1*1 }{10^{2} }

/F/=9*10^{7} N

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