Question

Calculate the force between two touching fruits each with a radius of 0.08 m and a mass of 0.45 Kg.

Answer 1

Answer:

Newton's Law of universal gravitation is:

F

=

G

m

1

m

2

r

2

[1]

Where G is the gravitational constant,

m

1

and

m

2

are the masses of the objects, and r is the distance between the centers.

Explanation:

Given that the objects are touching and their radius

0.080

m

, then

r

=

0.080

m

+

0.080

m

=

0.160

m

We are given that

m

1

=

m

2

=

0.45

kg

We know that

G

=

6.674

×

10

−

11

m

3

kg

−

1

s

−

2

Substitute this information into equation [1]:

F

=

(

6.674

×

10

−

11

m

3

kg

−

1

s

−

2

)

(

0.45

kg

)

(

0.45

kg

)

(

0.160

m

)

2

F

≈

5.28

×

10

−

10

N

Explanation:

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