Question

Calculate the force of address and between 2 bodies with mass of 50kg and 75kg if distance between them is 15 m

Answer 1

Your Answer :

Given :

Mass of the 1st body (M1) = 50kg

Mass of the 2nd body(M2) = 75kg

Distance between the two bodies = 15 meters.

Required to find :

1. Force of attraction between them.

solution:

Before coming to the question. you should know about the " Newton's Universal Law of Gravitation ".

This law states that ;

"Every object in the universe attracts every other object with some force which is directly proportional to the mass of the object and inversely proportional to the square of the distance between them "

Simply the law means,

every one attracts every other thing with some force.

This force which is attracting depends upon two factors ;

1. Mass 2. Distance between them .

The force of attraction will be more if the mass is more .

similarly if mass is less force of attraction is less.

And , if the distance is more force is less

similarly, if distance is less force is more.

So, Now let's Slove the above question:

We need to use a formula to solve this problem.

The formula is

$force = \frac { Gm1m2}{ {r}^{2} }$

Here ,

G = Universal constant that is 6.67×10^11 N m^2/kg^2

m1 and m2 = mass of the two bodies

r^2 = square of the distance between them

$force = \frac{6.67 \times {10}^{ - 11} \times 0.5 \times {10}^{2} \times 0.75 \times {2}^{2} }{15 \times 15}$

$force = \frac{6.67 \times 0.5 \times 0.75 \times {10}^{ - 11} \times {10}^{2} \times {10}^{2} }{15 \times 15} \\ force = \frac{6.67 \times 0.5 \times 0.75 \times {10}^{ - 11 + 2 + 2} }{15 \times 15} \\ force = \frac{ 6.67 \times 0.5 \times 0.75 \times {10}^{ - 7}}{15 \times 15} \\ force = \frac{2.501 \times {10}^{ - 7} }{225} \\ force = 0.0111 \times {10}^{ - 7} newtons$

Therefore,

force of attraction = 0.0111×10^-7 Newton.

This force of attraction is very negligible.

so the body will not be attracted by each other.

Answer 2

Answer:

Your Answer :

Given :

Mass of the 1st body (M1) = 50kg

Mass of the 2nd body(M2) = 75kg

Distance between the two bodies = 15 meters.

Required to find :

Force of attraction between them.

solution:

Before coming to the question. you should know about the " Newton's Universal Law of Gravitation ".

This law states that ;

"Every object in the universe attracts every other object with some force which is directly proportional to the mass of the object and inversely proportional to the square of the distance between them "

Simply the law means,

every one attracts every other thing with some force.

This force which is attracting depends upon two factors ;

1. Mass 2. Distance between them .

The force of attraction will be more if the mass is more .

similarly if mass is less force of attraction is less.

And , if the distance is more force is less

similarly, if distance is less force is more.

So, Now let's Slove the above question:

We need to use a formula to solve this problem.

The formula is

force = \frac { Gm1m2}{ {r}^{2} }force=

r

2

Gm1m2

Here ,

G = Universal constant that is 6.67×10^11 N m^2/kg^2

m1 and m2 = mass of the two bodies

r^2 = square of the distance between them

force = \frac{6.67 \times {10}^{ - 11} \times 0.5 \times {10}^{2} \times 0.75 \times {2}^{2} }{15 \times 15}force=

15×15

6.67×10

−11

×0.5×10

2

×0.75×2

2

\begin{gathered}force = \frac{6.67 \times 0.5 \times 0.75 \times {10}^{ - 11} \times {10}^{2} \times {10}^{2} }{15 \times 15} \\ force = \frac{6.67 \times 0.5 \times 0.75 \times {10}^{ - 11 + 2 + 2} }{15 \times 15} \\ force = \frac{ 6.67 \times 0.5 \times 0.75 \times {10}^{ - 7}}{15 \times 15} \\ force = \frac{2.501 \times {10}^{ - 7} }{225} \\ force = 0.0111 \times {10}^{ - 7} newtons\end{gathered}

force=

15×15

6.67×0.5×0.75×10

−11

×10

2

×10

2

force=

15×15

6.67×0.5×0.75×10

−11+2+2

force=

15×15

6.67×0.5×0.75×10

−7

force=

225

2.501×10

−7

force=0.0111×10

−7

newtons

Therefore,

force of attraction = 0.0111×10^-7 Newton.

This force of attraction is very negligible.

so the body will not be attracted by each other.