Question

Calculate the force of attraction between two metal sphere each of 90 kg if the distance between the centre is 40 cm

Answer 1

Answer:

F = 33.77 × 10⁻⁷ N

Explanation:

Given :

Two metals of same masses of 90 kg each .

Distance between them is 40 cm .

In term of meters :

Distance = 0.4 m

We have find  force of attraction

We know formula for it .

F = G M m / R²

Putting values here we get :

F = 6.67 × 10⁻¹¹ × 90 × 90 / ( 4.0 × 10⁻² ) ² N

F = 6.67 × 10⁻¹¹ × 81 × 10⁵ / 1.6 N

F = 6.67 × 81 × 10⁻⁶ / 1.6 N

F = 6.67 × 50.625  × 10⁻⁶ N

F = 337.67 × 10⁻⁶ N

F = 33.77 × 10⁻⁷ N

Hence we get answer .

Answer 2

Answer :-

Force of attraction between two metal sphere is 33.77 × 10^-7 N .

Explanation :-

Given :-

m1 = 90 kg

m2 = 90 kg

distance between the centre = R = 40 cm

R = 40 × 10⁻² m = 0.4 m

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To find :-

Force of attraction = F = ?

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Solution :-

We know that,

F = G m1 m2 / R²

➟ F = 6.67 × 10^-11 × 90 × 90 / (0.4)²

➟ F = 6.67 × 10^-11 × 81 × 10² / 0.16

➟ F = (540.27 × 10^-9) / (16 × 10^-2)

➟ F = 33.77 × 10^-7 N

OR

➟ F = 3.377 × 10^-6 N

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∴ Force of attraction between two metal sphere is 33.77 × 10^-7 N .

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