Question

Calculate the force of gravitation between a man weighting 80 kg and a boy weighting 60 kg standing 2 metres apart.
(take G = 6.7×10^-11 Nm^2/kg^2)

Answer 1

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Answer 2

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Mass of the man (m₁) = 80 kg
Mass of the boy (m₂) = 60 kg

Distance between the man and the boy
(d) = 2m

Gravitational constant (G) = 6.7 × 10-¹¹ N m²/kg²

The force exerted by the man on the boy is given by the formula for Newton's Universal law of gravitation, i.e.

$\boxed{F \: = G \frac{m1m2}{d2} }$

Putting the given value in the above formula, we get

$F \: = \frac{6.7 \times {10}^{ - 11} N {m}^{2}/ \: {kg}^{2} \times 80kg \: \times 60kg }{ {(2m)}^{2} }$


$= \frac{6.7 \times {10}^{ - 11} \times 80 \times 60(N {m}^{2} {kg}^{2} ). {kg}^{2} }{4 {m}^{2} }$

$F \: = 8.04 \times {10}^{ - 8} n$

Thus, the gravitation force exerted by the man on the boy is 8.04 × 10-⁸ N.

This is an extremely small force.

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