Question

calculate the force of gravitation due to Earth on a ball of mass 1 kg lying on the ground .(Mass of Earth =6×10*24;Radius =6.4×10*3 km;G=6.7×10*-11Nm*2 or Kg*2

Answer 1

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Answer 2

Given :

Mass (m) = 1 Kg

Mass of the earth (M) = 6 × $10^{24}$ Kg

Radius (r) = 6.4 × $10^{3}$ Km = 6.4 × $10^{6}$ m

G = 6.7 × $10^{-11}$ Nm²/kg²

To Find :

The force of gravitation due to Earth on a ball of mass 1 kg lying on the ground.

Solution :

Any two particle in the universe attract each other along a straight line joining them. The magnitude of this force of attraction is directly proportional to the product of the masses of these two particles and is inversely proportional to the square of the linear distance between them.

 Force (F) = $\frac{GMm}{r^{2} }$

            F   =  $\frac{6.7 * 10^{-11}*6 * 10^{24} * 1}{(6.4 * 10^{6} )^{2} }$

            F   =  $\frac{40.2 * 10^{13} }{(6.4 * 10^{6}) ^{2} }$

            F   = 9.81 N

∴ The Force of gravitation due to Earth on a ball of mass 1 kg lying on the ground is 9.81 N.