Question

calculate the force required to stop a car weighing 1500kg and moving at a velocity of 30m/s, in 10 seconds​

Answer 1

Answer:

Hope it helps you!

Explanation:

Here,

initial velocity of car(u)=0ms

−1

final velocity of car (v)=30ms

−1

time(t)=10s

we know,

v=u+at

30=0+a(10)

a=3ms

−2

we know,

F=ma

=1500×3

or F=4500N

Answer 2

Answer:

• Mass of the car (m) = 1500 kg
• Time taken (t) = 10 seconds
• Initial Velocity (u) = 0 m/s
• Final Velocity (v) = 30 m/s

We are supposed to calculate the Force required to stop the car.

First we need to calculate Acceleration.

Using First equation of motion :]

• v = u + at

Plug in the given values :

$\sf => v = u + at$

$\sf => 30 = 0 + a(10)$

$\sf => a = \dfrac{30}{10}$

$=> \textsf{ \textbf{a = 3 m/s ^2 }}$

Now, we can use value of a in Newton's second law and find the force required to stop the car :]

$\sf => Force = mass \times Acceleration$

$\sf => Force =1500 \times 3$

$=> \textsf{ \textbf{ Force = 45000 N}}$

Therefore,calculate the force required to stop a car is 45000 N.