Question

Calculate the foude's number for a channel
having discharge, as 261.03m/s. Cross
Secton area if 42m^2 and top width. being 6m​

Answer 1

Given:

Discharge $Q=261.03\ m/s$

Cross section area $A= 42\ m^{2}$

top width, $T$$=6\ m$

To Find:  Calculate foude's number for a channel

Step-by-step explanation:

• Volume of the channel

    $V=\dfrac{Q}{A} \\=\dfrac{261.03}{42\m}\\V=6.215\ m/s$

• Diameter

      $D=\dfrac{A}{T}\\=\dfrac{42}{6}\\D=7\ m$

• foude's number for a channel

   $F_{r}=\dfrac{V}{\sqrt{gD} }$

    $=\dfrac{6.215}{\sqrt{9.8\times7}}\\\\=0.75$

• The foud's number shows it is subcritical.