Question

Calculate the freezing point of the solution when 31g of ethylene glycol (C2H6O2) is dissolved in 500g of water. (Kf for water = 1.86 K kg mol -1 ) ​

Answer 1

hope this answer is hopeful

Answer 2

Answer :  Given: 31 g of ethyene glycol is dissolved in 500g of water.

The freezing point of pure water is 273.15 K. On dissolving ethylene glycol, freezing point, being a colligative property, will be lowered.

AT= = K W × 1000 M.x W

We are given that

K+ for water=1.86 K kg mol-1

Mass of solute, w=31 g

Molar mass of solute, M, 2 x2 + 1x6+ 16 x 2

= 62 g mol-1

Mass of water, W=500 g

31 x 1000

.. AT = 1.86 ×

62 x 500

= 1.86 K

Hence, the freezing point of the solution,

Tf 273.15 K-1.86 K

= 271.29 K

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