Question

calculate the frequency of radiation , if an electron in hydrogen atom jumps from n2 to n1=2 [R=1.1×10^7]​

Answer 1

Answer:Wavelength of photon emitted due to electronic transition from  n  

1

​  

=3 to  n  

2

​  

=2 of hydrogen atom

λ

1

​  

=R(  

n  

2

2

​  

 

1

​  

−  

n  

1

2

​  

 

1

​  

)

∴    

λ

1

​  

=R(  

2  

2

 

1

​  

−  

3  

2

 

1

​  

)        ⟹λ=  

5R

36

​  

 

Thus frequency of photon     ν=  

λ

C

​  

=  

36

5RC

​

Explanation: