Question

Calculate the frequency of the second harmonic formed on
a string of length 0.5 m and mass 2 x 104 kg when stretched
with a tension of 20 N

(a) 274.4 Hz
(b) 744.2 Hz
(c) 44.72 Hz
(d) 447.2 Hz​

Answer 1

Given:

The length of string l= 0.5 m

The stretched mass 2×10⁻⁴

The tension on the string T= 20 N

To find:

The frequency of the second harmonic

Solution :

Formula for it is

The frequency of second harmonic is equal to 2 times of first harmonic

n₂=2n₁

As n₁=$\frac{1}{l} \sqrt{T/m}$

Now the mass per unit length = 2×10⁻⁴/0.5

m'=4×10⁻⁴

Putting the value in the above formula

n₂=2×$\frac{1}{0.5} \sqrt{200000/4}$

n₂=447.2 Hz

So the frequency of second harmonic be 447.2 Hz

Answer 2

Answer:

hope it's help full for u