Question

Calculate the frequency of the spectral line corresponding to n1 =2 & n2 = 4. To which spectral series does this line belong?

Answer 1

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Answer 2

The correct answer is "$6.15\times 10^{15} \ Hz$".

Explanation:

According to the question,

The energy (E) will be:

= $13.6(\frac{1}{n_1^2}-\frac{1}{n_2^2})eV$

= $13.6(\frac{1}{4}-\frac{1}{16} )$

= $13.6\times \frac{3}{16} \ eV$

As we know,

⇒ $e = hv$

or,

⇒ $v= \frac{E}{h}$

By substituting the value, we get

⇒ $h = 6.63\times 10^{-34} \ Js$

      $=1.6\times 10^{-19} \ J$

hence,

The frequency will be:

⇒ $v = \frac{13.6\times 1.6\times 10^{-19}}{6.63\times 10^{-34}}\times \frac{3}{16}$

      $=6.15\times 10^{15} \ Hz$

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