* Calculate the frequency of yellow light of wavelength 5500 A. The speed of light is 3 X 10 8 ms-1 ? * The frequency range of visible light is from 3.75 X 10 14 Hz to 7.5 X 10 14 Hz. Calculate its wavelength range. Take speed of light = 3 X 10 8 ms -1.
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Answered by
14
frequency = velocity of light/wavelenght
=3x10 8 / 5500x10 -10
= 5.4x10 14Hz
wavelengh 1 = c/f1
=3x10 8 / 3.75x10 14
=0.8 x 10 -6
=8000 A
wavelenght 2 = c/f2
= 3x10 8 / 7.5x10 14
=0.4 x 10 -6
=4000 A
therefore,wavelength range is 4000 A to 8000 A
=3x10 8 / 5500x10 -10
= 5.4x10 14Hz
wavelengh 1 = c/f1
=3x10 8 / 3.75x10 14
=0.8 x 10 -6
=8000 A
wavelenght 2 = c/f2
= 3x10 8 / 7.5x10 14
=0.4 x 10 -6
=4000 A
therefore,wavelength range is 4000 A to 8000 A
Answered by
1
c = vλ or we can write this as: λ = c/v
First of all we will consider the first case:
λ₁ = c/v₁
c = 3 x 10⁸ m/s
v₁ = 3.75 x 10¹⁴ Hz
λ₁ = 3 x 10⁸ / 3.75 x 10¹⁴
= 0.8 x 10⁻⁶ m
Now we will consider the second case
λ₂ = c/v₂
c = 3 x 10⁸ m/s
v₂ = 7.5 x 10¹⁴ Hz
λ₂ = 3 x 10⁸ / 7.5 x 10¹⁴
= 0.4 x 10⁻⁶ m
So the wavelength range will be
0.4 x 10⁻⁶ m - 0.8 x 10⁻⁶ m
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