Question

Calculate the gram molecular mass of N2, if 360 cm³ at S.T.P
Weighs 0.45g.​

Answer 1

$\: \:$

the mass of 22.4 L of a gas at S.T.P is equal to its gram molecular mass.

=>$360 {cm}^{3} N_{2} \: at \: S.T.P \: weigh \: 0.4g$

=>$22 ,400 {cm}^{3} \: of \: N_{2} \: will \: weigh$

=>$\frac{0.45}{360} \times 22,400 = 28g$

Gram molecular Mass of

$\:\N_2=28\:$

Answer 2

Explanation:

\: \:

the mass of 22.4 L of a gas at S.T.P is equal to its gram molecular mass.

=>360 {cm}^{3} N_{2} \: at \: S.T.P \: weigh \: 0.4g360cm

3

N

2

atS.T.Pweigh0.4g

=>22 ,400 {cm}^{3} \: of \: N_{2} \: will \: weigh22,400cm

3

ofN

2

willweigh

=>\frac{0.45}{360} \times 22,400 = 28g

360

0.45

×22,400=28g

Gram molecular Mass of

\:\N_2=28\:N

2

=28