Question

calculate the gravitational acceleration at a distance twice the radius of the earth above the surface of the earth.​

Answer 1

heyaa .....

g = Gmr2

r is the distance to the center of the earth.

Twice the radius of Earth above the surface would increase the distance by a factor of three, therefore gravity would reduce by a factor of nine.

g/9 = 1.0896 meters/s^2..

hope it helps u....☺☺

Answer 2

Given :

Object is placed at the height of twice the radius of earth above the surface of the earth.​

Therefore , $h=2R+R=3R$ . ( Here , R is radius of earth )

To find :

The gravitational acceleration at a distance twice the radius of the earth above the surface of the earth.​

Solution :

We know , the acceleration due to gravity at a height h is given by :

$g'=\dfrac{g}{(1+\dfrac{h}{R})^2}$

( Here , R is radius of earth )

Putting , value of h = 3R in above equation .

We get :

$g'=\dfrac{g}{(1+\dfrac{3R}{R})^2}\\\\\\g'=\dfrac{g}{4^2}\\\\g'=\dfrac{g}{16}$

Therefore , the  the gravitational acceleration at a distance twice the radius of the earth above the surface of the earth  is  $\dfrac{g}{16}$ .

Learn More :

Gravitation

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