Question

calculate the gravitational force between a 10kg ball and a 20kg ball placed at a separation of 5meter​

Answer 1

Given:-

→ Mass of the 1st ball = 10kg

→ Mass of the 2nd ball = 20kg

→ Distance of separation between

the balls = 5m

To find:-

→ Gravitational force between the balls

Solution:-

By Newton's Universal Law of Gravitation, we know that :-

F = GMm/r²

Where :-

• F is the gravitational force between

the bodies.

• G is Universal Gravitational Constant.

• M is mass of the 1st body.

• m is mass of the 2nd body.

• r is the distance of separation between

the bodies.

• Value of G = 6.67×10⁻¹¹ Nm²/kg²

By substituting values in the above equation, we get:-

=> F = 6.67×10⁻¹¹×10×20/(5)²

=> F = 6.67×10⁻¹¹×200/25

=> F = 6.67×8×10⁻¹¹

=> F = 53.36×10⁻¹¹

=> F = 5.336×10⁻¹⁰ N

Thus, gravitational force between the balls is 5.336×10⁻¹⁰ N .

Answer 2

Required Answer:-

Given:

• Mass of first ball = 10kg.
• Mass of second ball = 20kg.
• Distance of Separation between the balls = 5m.

To find:

• Gravitational Force between the balls.

Answer:

• The gravitational force between the two balls is $\sf 5.336 \times 10^{-10}N$

Solution:

By Universal Law of Gravitation,

$\sf \boxed{\sf F = \frac{GMm}{r^{2}}}$

Where,

1. F is the gravitational force between two bodies.
2. G is Universal Gravitational Constant. (Approximately equal to $\sf 6.67 \times {10}^{-11} Nm^{2}kg^{-2}$)
3. M is the mass of the first body.
4. m is the mass of the second body and,
5. r is the distance of separation between the two bodies.

Substituting the values, we get,

➡ F = 6.67/10¹¹ × 10 × 20/(5 × 5)

➡ F = 6.67/10¹¹ × 200/25

➡ F = 6.67/10¹¹ × 8

➡ F = (6.67 × 8)/10¹¹

➡ F = 53.36/10¹¹

➡ $\sf F = 5.336 \times 10^{-10}N$

Thus, the gravitational force between the two balls is $\sf 5.336 \times 10^{-10}N$