Question

Calculate the gravitational force between earth and moon . The mass of earth is 6 x 10^24 kg and that of moon is 7.3x 10^22 kg and the distance between them is 3.84 x 10^5 km.

Answer 1

Answer:

2.025

⋅

10

20

,

0.002759

Explanation:

a)

F

=

G

(

m

1

)

(

m

2

)

r

2

F

=

(

6.67300

×

10

−

11

)

(

7.34

⋅

10

22

k

g

)

5.97

⋅

10

24

k

g

(

3.8

⋅

10

8

m

)

2

=

2.025

⋅

10

20

b) The field is just G(m)/r^2

(

6.67300

⋅

10

−

11

)

5.97

⋅

10

24

k

g

(

3.8

⋅

10

8

m

)

2

=

0.002759

Answer 2

$\huge \sf {\fbox{\fbox{\red{\fbox{Answer:}}}}}$

$\huge \bf{Given:-}$

$\sf {→Mass \: of \: the \: earth,m_1 = 6 \times{{10}^{24} }}$

$\sf {→Mass \: of \: the \: moon,m_2 = 7.4\times{{10}^{22} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{5} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = (3.84\times{{10}^{5} \times 1000)m }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{8}m}}$

$\huge \bf{To \: find:- }$

$\sf{⇒Force \: exerted \: to \: one \: body \: to \: another \: body.}$

$\huge \bf{Formula \: used: - }$

$\leadsto\sf{F =G \times \frac{m_1 \times m_2}{r^2} }$

$\huge \bf{Concept \: used: - }$

$\sf{Gravitational \: constant,G=6.7 \times {10}^{- 11N} N{m}^{2}k {g}^{ - 2} }$

$\huge\bf{According \: to \: Question:-}$

$\bf{F = \frac{6.7 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 7.4 \times {10}^{22}} {(3.84 \times {10}^{8} )^{2} } = 2.01 \times {10}^{20} newtons}$

$\sf\longmapsto{2.01 \times {10}^{20} newtons}$

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